cot arc sec(1517/165)
=cot arc tan√[(1517/165)²-1]
=cot arc ran(1508/165)
=165/1508
以上解答满意了么?
x = arcsec(1517/165)
则 secx = 1517/165
cotx = 165/√(1517^2 - 165^2 ) ] = 165/1508;
故 cot [ arcsec(1517/165) ] = cotx = 165/1508 。
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